HA3-2557-9 INTERSIL [Intersil Corporation], HA3-2557-9 Datasheet - Page 4

• Manufacturer Part Number: HA3-2557-9
• Description: 130MHz, Four Quadrant, Current Output Analog Multiplier
• Manufacturer: INTERSIL [Intersil Corporation]

internal reference with the V
to maintain the output of the multiplier within the normal oper-
ating range of ±1.6mA when full scale inputs are applied.
Typical Applications
Communication Applications
The multiplier function of the HA-2557 has applications in
AM Signal Generation, Synchronous AM Detection and
Phase Detection. These circuit configurations are shown in
Figure 2, Figure 3 and Figure 4. By feeding a signal into both
X and Y inputs a Square function results that is useful as a
Frequency Doubler as shown in Figure 5. The HA-2557 is
particularly useful in applications that require the interaction
of high speed signals. Both inputs X and Y have similar wide
bandwidth and input characteristics. This is unlike earlier
products where one input was dedicated to a slow moving
control function as is required for Automatic Gain Control.
The HA-2557 is versatile enough for both.
AM SIGNAL
CARRIER
CARRIER
CCOS(ω
I OUT
ACOS(ω
AUDIO
FIGURE 3. SYNCHRONOUS AM DETECTION
LIKE THE FREQUENCY DOUBLER YOU GET
AUDIO CENTERED AT DC AND 2F
FIGURE 2. AM SIGNAL GENERATION
=
C
Α
---------------- -
20kVΩ
τ)
τ)
AC
V
V
Y
1/10kVΩ
V
V
+
X
X
Y
1/10kVΩ
V
V
+
V
V
(
-
-
Co s ω C
Y
X
X
Y
+
+
+
-
-
+
-
-
(
+
+
-
-
REF
–
ω A
X
Y
pin. The scale factor is used
Y
X
X
)
τ
X
+
C os ω C
C
.
R
(
R
Z
Z
+
ω A
I
)
OUT
τ
)
I
OUT
HA-2557
8-4
Although the X and Y inputs have similar AC characteristics,
they are not the same. The designer should consider input
parameters such as small signal bandwidth and AC
feedthrough to get the most performance from the HA-2557.
The Y channel is the faster of the two inputs with a small sig-
nal bandwidth of typically 130MHz verses 75MHz for the X
channel. Therefore in AM Signal Generation, the best perfor-
mance will be obtained with the Carrier applied to the Y
channel and the modulation signal (lower frequency) applied
to the X channel.
WHICH EVALUATES TO:
ACOS(ωτ+φ)
ACOS(ωτ)
ACOS(ωτ)
I
OUT
DC COMPONENT IS PROPORTIONAL TO COS(Φ)
FIGURE 5. FREQUENCY DOUBLER
I
(
=
OUT
ACos ωτ
FIGURE 4. PHASE DETECTION
------------------ - Cos φ ( )
20kVΩ
A
1/10kVΩ
=
V
V
2
V
V
(
X
Y
Y
X
---------- - 1
20K
+
+
A
-
-
V
V
V
(
V
2
Y
)
X
Y
X
×
+
+
+
+
-
-
1/10kVΩ
(
-
-
ACos ω τ
+
+
+
-
-
Cos 2ωτ
+
X
Y
(
Cos 2ωτ
(
X
X
Y
)
)
(
X
=
)
)
R
10kVΩ I
Z
+
R
φ
Z
)
)
(
OUT
I
OUT
)
I
OUT