BC557BRL1 ON Semiconductor, BC557BRL1 Datasheet - Page 3

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BC557BRL1

Manufacturer Part Number
BC557BRL1
Description
Transistors Bipolar - BJT 100mA 50V PNP
Manufacturer
ON Semiconductor
Datasheet

Specifications of BC557BRL1

Product Category
Transistors Bipolar - BJT
Rohs
yes
Configuration
Single
Transistor Polarity
PNP
Collector- Base Voltage Vcbo
- 50 V
Collector- Emitter Voltage Vceo Max
- 45 V
Emitter- Base Voltage Vebo
5 V
Collector-emitter Saturation Voltage
- 45 V
Maximum Dc Collector Current
0.1 A
Gain Bandwidth Product Ft
320 MHz
Dc Collector/base Gain Hfe Min
180 at 2 mA at 5 V
Maximum Operating Temperature
+ 150 C
Mounting Style
Through Hole
Package / Case
TO-92-3 (TO-226)
Continuous Collector Current
- 0.1 A
Maximum Power Dissipation
625 mW
Minimum Operating Temperature
- 55 C
Factory Pack Quantity
2000

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
BC557BRL1G
Manufacturer:
ON Semiconductor
Quantity:
23
−2.0
−1.6
−1.2
−0.8
−0.4
2.0
1.5
1.0
0.7
0.5
0.3
0.2
7.0
5.0
3.0
2.0
1.0
10
0
−0.4
−0.2
I
−10 mA
−0.02
C
−0.6
V
T
=
A
CE
−0.5 −1.0
Figure 1. Normalized DC Current Gain
Figure 3. Collector Saturation Region
= 25°C
= −10 V
−1.0
I
C
V
Figure 5. Capacitances
−0.1
I
, COLLECTOR CURRENT (mAdc)
R
C
, REVERSE VOLTAGE (VOLTS)
−2.0
= −20 mA
−2.0
I
B
, BASE CURRENT (mA)
−5.0 −10
I
C
−4.0 −6.0
C
= −50 mA
ib
C
−1.0
ob
BC556B, BC557A, B, C, BC558B
−20
T
−10
A
= 25°C
T
I
C
I
A
C
= −200 mA
= 25°C
−50 −100 −200
= −100 mA
−20 −30 −40
http://onsemi.com
−10
BC557/BC558
−20
3
−1.0
−0.9
−0.8
−0.7
−0.6
−0.5
−0.4
−0.3
−0.2
−0.1
400
300
200
100
150
1.0
1.2
1.6
2.0
2.4
2.8
80
60
40
30
20
0
−0.5
−0.1 −0.2
Figure 4. Base−Emitter Temperature Coefficient
T
Figure 6. Current−Gain − Bandwidth Product
A
−0.2
Figure 2. “Saturation” and “On” Voltages
= 25°C
−55°C to +125°C
−1.0
−0.5 −1.0 −2.0
I
I
C
C
I
−2.0 −3.0
, COLLECTOR CURRENT (mAdc)
C
, COLLECTOR CURRENT (mAdc)
, COLLECTOR CURRENT (mA)
V
−1.0
V
V
BE(on)
CE(sat)
BE(sat)
@ V
@ I
@ I
−5.0
CE
C
C
/I
/I
B
= −10 V
B
= 10
−5.0
= 10
−10
−10
−10
−20
−20 −30
V
T
A
CE
= 25°C
= −10 V
−50 −100
−100
−50

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