MC33364D ON Semiconductor, MC33364D Datasheet - Page 11

• Manufacturer Part Number: MC33364D
• Description: IC CTRLR SMPS OTP UVLO 16SOIC
• Manufacturer: ON Semiconductor
• Series: GreenLine™r

Specifications of MC33364D

• Output Isolation: Isolated
• Frequency Range: 104 ~ 800kHz
• Voltage - Input: 7.6 ~ 16 V
• Voltage - Output: 700V
• Power (watts): 550mW
• Operating Temperature: -25°C ~ 150°C
• Package / Case: 16-SOIC (0.154", 3.90mm Width) 14 leads
• Number Of Outputs: 1
• Output Voltage: 4.90 V to 5.20 V
• Output Current: 600 mA
• Mounting Style: SMD/SMT
• Operating Supply Voltage: 16 V
• Maximum Operating Temperature: + 125 C
• Fall Time: 28 ns
• Minimum Operating Temperature: - 25 C
• Rise Time: 67 ns
• Synchronous Pin: No
• Topology: Flyback
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Other names: MC33364DOS

of 100% with 25% tolerance. When the TL431 is full- -on,
5 mA will be drawn from the transistor within the
MOC8102. The transistor should be in saturated state at that
time, so its collector resistor must be
reference voltage to the feedback pin of the MC33364, the
external resistor can have a higher value
through the optoisolator diode and the voltage sense divider
on the secondary side.
heavy load resistance is given by:
R ext = R3 =
The MOC8102 has a typical current transfer ratio (CTR)
Since a resistor of 5.0 k is internally connected from the
This completes the design of the voltage feedback circuit.
In no load condition there is only a current flowing
The load at that condition is given by:
The output filter pole at no load is:
In heavy load condition the I
The output filter pole at heavy load of this output is
f
R
ph
collector
=
R
R
(2π R
noload
heavy
f
=
ph
heavy
(R
V
(R
=
=
=
=
=
1
int
ref
int
) − (R
(I
(5.0 mA + 0.25 mA)
(2π)(1143)(300 mF)
V out
( 2π R
I
I out
LED
C out )
− V sat
LED
)(R
V out
collector
=
+ I
noload
collector
=
6.0 V
6.0 V
2.0 A
1
1
=
div
LED
(2π)(3)(300 mF)
5.0 V − 0.3 V
)
)
C out )
and I
= 3.0 Ω
)
5.0 mA
= 1157 Ω ≈ 1200 Ω
=
1
div
5.0 k − 940
(5.0 k)(940)
= 0.46 Hz
= 1143 Ω
is negligible. The
= 177 Hz
= 940 Ω
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11
high input voltage will be:
approximately:
bandwidth is calculated at the rated load because that yields
the bandwidth condition, which is:
The output resistance of the voltage sense divider is given by
the parallel combination of resistors in the divider:
light load filter pole:
Gc = 20 log
The gain exhibited by the open loop power supply at the
The
The gain needed by the error amplifier to achieve this
The gain in absolute terms is:
Now the compensation circuit elements can be calculated.
The compensation zero must be placed at or below the
A =
R
in
C8 =

C7 =
= R upper || R

A c = 10 (Gc∕20) = 10 (14.14∕20) = 5.1
(V
V
maximum
in max
in max
R9 = (Ac) (R

f c = fs min
2π (A c ) (R


2π (R9) (f pn )
f
f c
ph
)(V error )(Np)
− V out

5
1
1
− A = 20 log
lower
in
recommended
=
in
) (f c )

) = 29.75 k ≈ 30 k
2
70 kHz

= 10 k || 14 k = 5833 Ω
Ns
= 11.63 mF ≈ 10 mF

5

= 382 pF ≈ 390 pF
= 15.53 = 23.82 dB
=
= 14 kHz

 382 V − 6.0 V  2 (7)
(382 V)(1.2 V)(139)
14 kHz
177
bandwidth

= 14.14 dB
− 23.82 dB
is