MC68HC908GT16CFB Freescale Semiconductor, MC68HC908GT16CFB Datasheet - Page 93

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MC68HC908GT16CFB

Manufacturer Part Number
MC68HC908GT16CFB
Description
IC MCU 16K FLASH 8MHZ SPI 44PQFP
Manufacturer
Freescale Semiconductor
Series
HC08r
Datasheet

Specifications of MC68HC908GT16CFB

Core Processor
HC08
Core Size
8-Bit
Speed
8MHz
Connectivity
SCI, SPI
Peripherals
LVD, POR, PWM
Number Of I /o
36
Program Memory Size
16KB (16K x 8)
Program Memory Type
FLASH
Ram Size
512 x 8
Voltage - Supply (vcc/vdd)
2.7 V ~ 5.5 V
Data Converters
A/D 8x8b
Oscillator Type
Internal
Operating Temperature
-40°C ~ 85°C
Package / Case
44-QFP
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Eeprom Size
-

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Settling time depends primarily on how many corrections it takes to change the clock period and the
period of each correction. Since the corrections require four periods of the low-frequency base clock
(4*τ
IBASE, each correction takes 4*N*τ
7.4.6.1 Settling to Within 15 Percent
When the error is greater than 15 percent, the filter takes eight corrections to double or halve the clock
period. Due to how the DCO increases or decreases the clock period, the total period of these eight
corrections is approximately 11 times the period of the fastest correction. (If the corrections were perfectly
linear, the total period would be 11.5 times the minimum period; however, the ring must be slightly
nonlinear.) Therefore, the total time it takes to double or halve the clock period is 44*N*τ
If the clock period needs more than doubled or halved, the same relationship applies, only for each time
the clock period needs doubled, the total number of cycles doubles. That is, when transitioning from fast
to slow, going from the initial speed to half speed takes 44*N*τ
takes 88*N*τ
series can be expressed as (2
doubled or halved. Since 2
44*N*(τ
Note that increasing speed takes much longer than decreasing speed since N is higher. This can be
expressed in terms of the initial clock period (τ
7.4.6.2 Settling to Within 5 Percent
Once the clock period is within 15 percent of the desired clock period, the filter starts making smaller
adjustments. When between 15 percent and 5 percent error, each correction will adjust the clock period
between 1.61 percent and 2.94 percent. In this mode, a maximum of eight corrections will be required to
get to less than 5 percent error. Since the clock period is relatively close to desired, each correction takes
approximately the same period of time, or 4*τ
be set and the clock frequency is usable, although the error will be as high as 5 percent. The total time to
this point is:
7.4.6.3 Total Settling Time
Once the clock period is within 5 percent of the desired clock period, the filter starts making minimum
adjustments. In this mode, each correction will adjust the frequency between 0.202 percent and 0.368
percent. A maximum of 24 corrections will be required to get to the minimum error. Each correction takes
approximately the same period of time, or 4*τ
this makes 32 corrections (128*τ
minimum error is:
The equations for τ
the nominal. This means the variability in the ICLK frequency due to process, temperature, and voltage
must be considered. Additionally, other process factors and noise can affect the actual tolerances of the
points at which the filter changes modes. This means a worst case adjustment of up to 35 percent (ICLK
Freescale Semiconductor
IBASE
ICLKSLOW
), and since ICLK is N (the ICG multiply factor for the desired frequency) times faster than
ICLKFAST
–τ
15
ICLKFAST
MC68HC908GT16 • MC68HC908GT8 • MC68HC08GT16 Data Sheet, Rev. 5.0
, τ
; going from quarter speed to eighth speed takes 176*N*τ
5
, and τ
x
).
happens to be equal to τ
x
tot
–1)*44*N*τ
IBASE
τ
are dependent on the actual initial and final clock periods τ
tot
τ
5
ICLK
=
=
) to get from 15 percent to the minimum error. The total time to the
τ
abs 44N τ
abs 44N τ
. The period of ICLK, however, will vary as the corrections occur.
15
ICLKFAST
=
[
[
IBASE
IBASE
abs 44N τ
1
) minus the final clock period (τ
(
(
[
. Added to the corrections for 15 percent to 5 percent,
. At this point, the internal clock stable bit (ICGS) will
1
1
, where x is the number of times the speed needs
ICLKSLOW
τ
τ
2
2
(
)
)
1
]
]
+
+
32τ
128τ
τ
ICLKFAST
2
)
]
ICLKFAST
IBASE
IBASE
; from half speed to quarter speed
, the equation reduces to
ICLKFAST
2
) as such:
; and so on. This
ICLKFAST
1
Usage Notes
and τ
.
2
, not
93

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