LM2904D STMicroelectronics, LM2904D Datasheet - Page 10

IC OP AMP DUAL LO POWER 8-SOIC

LM2904D

Manufacturer Part Number
LM2904D
Description
IC OP AMP DUAL LO POWER 8-SOIC
Manufacturer
STMicroelectronics
Datasheet

Specifications of LM2904D

Amplifier Type
General Purpose
Number Of Circuits
2
Slew Rate
0.6 V/µs
Gain Bandwidth Product
1.1MHz
Current - Input Bias
20nA
Voltage - Input Offset
2000µV
Current - Supply
700µA
Current - Output / Channel
40mA
Voltage - Supply, Single/dual (±)
3 V ~ 30 V, ±1.5 V ~ 15 V
Operating Temperature
-40°C ~ 125°C
Mounting Type
Surface Mount
Package / Case
8-SOIC (3.9mm Width)
Number Of Channels
2
Common Mode Rejection Ratio (min)
70 dB
Input Offset Voltage
7 mV
Input Bias Current (max)
150 nA
Operating Supply Voltage
5 V, 9 V, 12 V, 15 V
Supply Current
1.2 mA
Maximum Power Dissipation
500 mW
Maximum Operating Temperature
+ 125 C
Minimum Operating Temperature
- 40 C
Dual Supply Voltage
+/- 3 V, +/- 5 V, +/- 9 V, +/- 12 V
Maximum Dual Supply Voltage
+/- 15 V
Minimum Dual Supply Voltage
+/- 1.5 V
Mounting Style
SMD/SMT
Shutdown
No
Supply Voltage (max)
30 V
Supply Voltage (min)
3 V
Technology
Bipolar
Voltage Gain Db
100 dB
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Output Type
-
-3db Bandwidth
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant

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Electrical characteristics
3.1
10/21
Figure 18. AC coupled inverting amplifier
Figure 20. Non-inverting DC gain
Figure 22. High input Z, DC differential
+
+V2
e
V1
I
~
10kΩ
V
R1
C
CC
I
10k Ω
If R1 = R5 and R3 = R4 = R6 = R7
eo = [ 1 +
As shown eo = 101 (e2 - e1)
100kΩ
100kΩ
10kΩ
R1
R1
R2
10μF
C1
Typical single-supply applications
amplifier
2R1
R2
LM2904
1M Ω
100kΩ
LM2904
R2
100kΩ
LM2904
1/2
R3
] (e2 - e1)
1/2
R
6.2k Ω
100kΩ
1/2
f
R2
R
B
(as shown A = -10)
A = -
100k Ω
V
e
C
R3
O
o
R1
R
+5V
0
f
e
10kΩ
o
A
0
R
V
V
L
= 1 +
(As shown
LM2904
100kΩ
e
1/2
I
R4
(mV)
R2
R1
Doc ID 2471 Rev 13
A
V
= 101)
2V
PP
V
o
Figure 19. AC coupled non-inverting amplifier
Figure 21. DC summing amplifier
Figure 23. Using symmetrical amplifiers to
0.1 μ F
C1
e
1.5MΩ
I
e
~
I
I
I
B
B
100kΩ
C
10 μ F
e
e
e
e
R1
I
I
1MΩ
C2
1
2
3
4
I
R3
reduce input current
2N 929
100kΩ
100kΩ
100kΩ
100kΩ
I
B
LM2904
LM2904
1/2
eo = e1 + e2 - e3 - e4
where (e1 + e2)
to keep eo
1MΩ
100kΩ
3M Ω
100kΩ
R2
1/2
6.2kΩ
R5
I
I
R4
B
B
R
0.001 μ F
B
100kΩ
V
CC
LM2904
0V
1/2
Input current compensation
(as shown A = 11)
A = 1 + R2
LM2904
C
(e3 + e4)
V
o
1/2
100kΩ
LM2904, LM2904A
e
e
o
R1
10k Ω
o
0
R
V
L
e
O
2V
PP

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