TS4909IQT STMicroelectronics, TS4909IQT Datasheet - Page 25

• Manufacturer Part Number: TS4909IQT
• Description: IC AMP AUDIO .158W STER AB 10DFN
• Manufacturer: STMicroelectronics
• Type: Class ABr

Specifications of TS4909IQT

• Output Type: Headphones, 2-Channel (Stereo)
• Max Output Power X Channels @ Load: 158mW x 2 @ 16 Ohm
• Voltage - Supply: 2.2 V ~ 5.5 V
• Features: Depop, Standby
• Mounting Type: Surface Mount
• Package / Case: 10-DFN
• Operational Class: Class-AB
• Audio Amplifier Output Configuration: 2-Channel Stereo
• Audio Amplifier Function: Headphone
• Total Harmonic Distortion: 0.3@16Ohm@90mW%
• Single Supply Voltage (typ): 3/5V
• Dual Supply Voltage (typ): Not RequiredV
• Supply Current (max): 4.8@5VmA
• Power Supply Requirement: Single
• Power Dissipation: 1.79W
• Rail/rail I/o Type: No
• Power Supply Rejection Ratio: 72dB
• Single Supply Voltage (min): 2.2V
• Single Supply Voltage (max): 5.5V
• Dual Supply Voltage (min): Not RequiredV
• Dual Supply Voltage (max): Not RequiredV
• Operating Temp Range: -40C to 85C
• Operating Temperature Classification: Industrial
• Mounting: Surface Mount
• Pin Count: 10
• Package Type: DFN
• For Use With: 497-6380 - BOARD DEMO FOR TS4909Q
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Other names: 497-5992-2

TS4909
Note:
4.4.2
Note:
and its value is:
This maximum value depends only on the power supply voltage and load values.
The efficiency is the ratio between the output power and the power supply:
The maximum theoretical value is reached when V
Phantom ground configuration
The average current delivered by the power supply voltage is:
Figure 81. Current delivered by power supply voltage in phantom ground
The power delivered by the power supply voltage is:
Therefore, the power dissipation by each amplifier is
and the maximum value is obtained when:
and its value is:
This maximum value depends only on power supply voltage and load values.
Vpeak/R
configuration
Icc
Icc (t)
AVG
L
0
Icc
AVG
T/2
P
diss
=
P
=
η
1
-- -
π
supply
P
P
∫
=
2 2V
---------------------- P
π
0
diss
diss
π R
η
------------------ -
P
V
---------------- -
P
=
supply
PEAK
T
MAX
R
MAX
OUT
=
∂P
∂
L
CC
-- -
4
π
L
P
V
diss
=
OUT
=
=
sin
CC
2V
-------------- - W
------------ - W
π
=
π
78.5%
V
I
OUT
2
2
t ( )
2
CC
CC
R
πV
-------------------- -
R
=
2
CC
2V
3T/2
L
t d
L
AVG
0
(
PEAK
(
–
CC
PEAK
=
P
(
)
W
)
OUT
2V
-------------------- - A
)
πR
PEAK
= V
(
W
L
)
2T
CC
( )
/2, so:
Time
Application information
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