STOD1812PUR STMicroelectronics, STOD1812PUR Datasheet - Page 11

IC PWR SUPPLY PMOLED 10-DFN

STOD1812PUR

Manufacturer Part Number
STOD1812PUR
Description
IC PWR SUPPLY PMOLED 10-DFN
Manufacturer
STMicroelectronics
Datasheet

Specifications of STOD1812PUR

Display Type
PMOLED
Configuration
Display Matrix
Current - Supply
1.3mA
Voltage - Supply
2.5 V ~ 5.5 V
Operating Temperature
-40°C ~ 125°C
Mounting Type
Surface Mount
Package / Case
10-DFN
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Interface
-
Digits Or Characters
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
497-6839-2

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
STOD1812PUR
Manufacturer:
ST
Quantity:
20 000
STOD1812
8
Figure 8.
Figure 10. Efficiency vs temperature
Figure 12. Line transient
V
I
= from 2.5 V to 3 V, I
100
100
100
100
T = 25 °C
90
90
80
80
70
70
60
60
50
50
40
40
90
90
80
80
70
70
60
60
50
50
40
40
-75
-75
0
0
V
V
-50
-50
I
I
= V
= V
Typical application performance
(V
20
20
Efficiency vs output current
EN
EN
-25
-25
O
= 3.6 V, I
= 3.6 V, I
= 18 V, L = 2.2 µH, C
O
0
0
40
40
= 120 mA, V
O
O
= from 5 mA to 120 mA, T = 25°C
= from 5 mA to 120 mA, T = 25°C
25
25
I
I
O
O
[mA]
[mA]
V
V
T [°C]
T [°C]
60
60
I
I
50
50
= V
= V
EN
EN
I
(t
75
75
= 3.6 V, I
= 3.6 V, I
RISE
80
80
100 125
100 125
= t
FALL
O
O
I
= 120 mA
= 120 mA
= C
100
100
) = 50µs,
O
150 175
150 175
= 4.7 µF, R
120
120
Figure 9.
Figure 11. Frequency vs temperature
Figure 13. Load transient response
V
V
I
I
O
O
= 3.6 V, I
100
100
2.5
2.5
2.3
2.3
2.1
2.1
1.9
1.9
1.7
1.7
1.5
1.5
1.3
1.3
1.1
1.1
0.9
0.9
0.7
0.7
0.5
0.5
1
T = 25 °C
90
90
80
80
70
70
60
60
50
50
40
40
= 270 kΩ , R
-75
-75
2.5
2.5
V
V
-50
-50
O
I
I
= V
= V
V
V
from 5mA to 120mA, t
IN
IN
= V
= V
Efficiency vs input voltage
EN
EN
3
3
-25
-25
EN
EN
= from 2.5 V to 5.5 V, I
= from 2.5 V to 5.5 V, I
= 3.6 V, I
= 3.6 V, I
2
Typical application performance
= 20 kΩ)
0
0
3.5
3.5
O
O
= 80 mA
= 80 mA
25
25
V
V
T [°C]
T [°C]
I
I
50
50
[V]
[V]
4
4
RISE
O
O
75
75
= 120 mA, T = 25 °C
= 120 mA, T = 25 °C
= t
4.5
4.5
FALL
100 125 150 175
100 125 150 175
= 10 µs,
5
5
11/19
5.5
5.5

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