L6563A STMicroelectronics, L6563A Datasheet - Page 24
![IC PFC CTRLR TRANSITION 14SOIC](/photos/6/57/65750/497-14-soic_sml.jpg)
L6563A
Manufacturer Part Number
L6563A
Description
IC PFC CTRLR TRANSITION 14SOIC
Manufacturer
STMicroelectronics
Datasheet
1.L6563ATR.pdf
(39 pages)
Specifications of L6563A
Mode
Discontinuous (Transition)
Current - Startup
50µA
Voltage - Supply
10.3 V ~ 22 V
Operating Temperature
-25°C ~ 125°C
Mounting Type
Surface Mount
Package / Case
14-SOIC (3.9mm Width), 14-SOL
Maximum Operating Temperature
+ 150 C
Mounting Style
SMD/SMT
Minimum Operating Temperature
- 25 C
For Use With
497-9082 - EVAL BOARD L6563 (200W)497-8850 - BOARD EVAL FOR L6563/STW55NM60N497-8834 - BOARD DEMO FOR L6563/LL6566A497-8429 - BOARD ADAPTER L6599/STP12NM50N497-5854 - DEMO BOARD FOR L6563497-5496 - EVAL BOARD FOR L6599497-5493 - EVAL BOARD FOR L6563
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Frequency - Switching
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Part Number:
L6563A
Manufacturer:
ST
Quantity:
20 000
Part Number:
L6563AD013TR
Manufacturer:
ST
Quantity:
20 000
Application information
24/39
to set the output voltage at the desired values use the following design procedure:
1.
Equation 6
and choose a value Vin
output voltage range below Vox (it will equal Vox if one chooses Vin
2.
Equation 7
and check that at minimum mains voltage Vin
0.65V.
3.
Equation 8
4.
Equation 9
Determine the input RMS voltage Vin
Determine the divider ratio of the MULT pin (pin 3) bias:
Determine R1, the upper resistor of the output divider:
Calculate the lower resistor R
R2
R
T
x
Vin
such that Vin
=
=
clamp
2.5 R1
2 k R1
⋅ ⋅
⋅
=
2
⋅
Vox Vo
-------------------------- - Vin
Vo
of the output divider and the adjustment resistor R
--------------------------------------------------------------------------------------------------
(
Vo
⋅
2
2
Vin
----------------------------- -
R1
Vo
–
= Vin
–
k
1
Vo
–
=
2
2
clamp
=
2.5
–
–
1
1
-----------------------
∆
---------- - 10
Vin
Vo
x
⋅
2 Vin
20
1
Vo
) Vin
< Vin
⋅
⋅
the peak voltage on pin 3 is greater than
1
3
that produces Vo = Vox:
1
Vin
⋅
2
–
x
2
2
clamp
6
Vox Vo
-------------------------- - Vin
Vo
–
–
Vin
(
Vo
2
. This will result in a limitation of the
–
–
1
2
Vo
–
2.5
1
2
⋅
) Vin
⋅
1
x
= Vin
1
clamp
L6563 - L6563A
)
T
: