2N6517 ON Semiconductor, 2N6517 Datasheet - Page 5

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2N6517

Manufacturer Part Number
2N6517
Description
TRANS NPN SS GP 350V TO92
Manufacturer
ON Semiconductor
Datasheet

Specifications of 2N6517

Transistor Type
NPN
Current - Collector (ic) (max)
500mA
Voltage - Collector Emitter Breakdown (max)
350V
Vce Saturation (max) @ Ib, Ic
1V @ 5mA, 50mA
Dc Current Gain (hfe) (min) @ Ic, Vce
20 @ 50mA, 10V
Power - Max
625mW
Frequency - Transition
200MHz
Mounting Type
Through Hole
Package / Case
TO-92-3 (Standard Body), TO-226
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Current - Collector Cutoff (max)
-
Other names
2N6517OS

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−0.5
−1.0
−1.5
−2.0
−2.5
100
1.4
1.2
1.0
0.8
0.6
0.4
0.2
2.5
2.0
1.5
1.0
0.5
7.0
5.0
3.0
2.0
1.0
70
50
30
20
10
0
0
1.0
1.0
0.2
R
R
qVC
qVB
Figure 8. Temperature Coefficients
0.5
2.0
2.0
for V
for V
3.0
1.0
BE
V
CE(sat)
3.0
V
Figure 6. “On” Voltages
Figure 10. Capacitance
BE(sat)
V
CE(sat)
NPN 2N6515, 2N6517
NPN 2N6515, 2N6517
V
NPN 2N6515, 2N6517
I
I
BE(on)
C
C
R
, COLLECTOR CURRENT (mA)
, COLLECTOR CURRENT (mA)
I C
T
I B
, REVERSE VOLTAGE (VOLTS)
J
2.0
5.0 7.0 10
= 25 C
5.0 7.0
@ I
@ I
+ 10
@ V
C
C
/I
/I
CE
B
B
5.0
= 10
= 10
C
= 10 V
eb
10
10
−55 C to 125 C
−55 C to
25 C to 125 C
25 C
20
20
C
20
cb
V
CE(sat)
30
30
2N6515, 2N6517, 2N6520
T
J
@ I
= 25 C
50 70
50 70
50 100
C
/I
B
http://onsemi.com
= 5.0
200
100
100
5
−1.4
−1.2
−1.0
−0.8
−0.6
−0.4
−0.2
−0.5
−1.0
−1.5
−2.0
−2.5
100
2.5
2.0
1.5
1.0
0.5
7.0
5.0
3.0
2.0
1.0
70
50
30
20
10
0
0
−1.0
−1.0
−0.2
R
R
Figure 9. Temperature Coefficients
qVC
qVB
−0.5 −1.0 −2.0
−2.0 −3.0
−2.0 −3.0
for V
for V
V
Figure 7. “On” Voltages
V
V
Figure 11. Capacitance
CE(sat)
CE(sat)
I C
I B
BE(sat)
BE(on)
BE
V
I
I
T
C
C
R
+ 10
J
, COLLECTOR CURRENT (mA)
, COLLECTOR CURRENT (mA)
, REVERSE VOLTAGE (VOLTS)
= 25 C
−5.0 −7.0 −10
@ V
@ I
−5.0 −7.0 −10
PNP 2N6520
PNP 2N6520
PNP 2N6520
@ I
C
C
CE
/I
/I
B
B
= −10 V
C
= 10
−5.0
= 10
eb
25 C to 125 C
−10
−55 C to
−20 −30
−20 −30
25 C
C
−20
cb
V
CE(sat)
−55 C to 125 C
T
−50
J
@ I
= 25 C
−50 −70
−50 −70
C
/I
−10
B
0
= 5.0
−100
−100
−20
0

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