aoz1014 Alpha & Omega Semiconductor, aoz1014 Datasheet - Page 10

• Manufacturer Part Number: aoz1014
• Description: Ezbuck 5a Simple Buck Regulator
• Manufacturer: Alpha & Omega Semiconductor

inductor value, switching frequency, output capacitor
value and ESR. It can be calculated by the equation
below:
where,
C
ESR
capacitor.
When low ESR ceramic capacitor is used as output
capacitor, the impedance of the capacitor at the switching
frequency dominates. Output ripple is mainly caused by
capacitor value and inductor ripple current. The output
ripple voltage calculation can be simplified to:
If the impedance of ESR at switching frequency
dominates, the output ripple voltage is mainly decided
by capacitor ESR and inductor ripple current. The output
ripple voltage calculation can be further simplified to:
For lower output ripple voltage across the entire operat-
ing temperature range, X5R or X7R dielectric type of
ceramic, or other low ESR tantalum capacitor or alumi-
num electrolytic capacitor may also be used as output
capacitors.
In a buck converter, output capacitor current is con-
tinuous. The RMS current of output capacitor is decided
by the peak to peak inductor ripple current. It can be
calculated by:
I
Usually, the ripple current rating of the output capacitor
is a smaller issue because of the low current stress.
When the buck inductor is selected to be very small
and inductor ripple current is high, output capacitor could
be overstressed.
Schottky Diode Selection
The external freewheeling diode supplies the current to
the inductor when the high side PMOS switch is off. To
reduce the losses due to the forward voltage drop and
recovery of diode, Schottky diode is recommended to
use. The maximum reverse voltage rating of the chosen
Schottky diode should be greater than the maximum
CO _RMS
O
V
V
V
Rev. 1.0 December 2006
is output capacitor value, and
O
O
CO
O
=
=
=
is the equivalent series resistance of the output
I
I
I
=
L
L
L
----------
12
ES R
-------------------------- -
8 f
I
L
ES R
1
CO
CO
C
O
+
-------------------------- -
8
f
1
C
O
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input voltage, and the current rating should be greater
than the maximum load current.
Loop Compensation
The AOZ1014 employs peak current mode control for
easy use and fast transient response. Peak current mode
control eliminates the double pole effect of the output
L&C filter. It greatly simplifies the compensation loop
design.
With peak current mode control, the buck power stage
can be simplified to be a one-pole and one-zero system
in frequency domain. The pole is dominant pole and can
be calculated by:
The zero is a ESR zero due to output capacitor and its
ESR. It is can be calculated by:
where;
C
R
ESR
The compensation design is actually to shape the
converter close loop transfer function to get desired gain
and phase. Several different types of compensation
networks can be used for AOZ1014. For most cases, a
series capacitor and resistor network connected to the
COMP pin sets the pole-zero and is adequate for a stable
high-bandwidth control loop.
In the AOZ1014, FB pin and COMP pin are the inverting
input and the output of internal transconductance error
amplifier. A series R and C compensation network
connected to COMP provides one pole and one zero.
The pole is:
where;
G
A/V,
G
C
f
f
f
P 1
P 2
Z 1
O
L
EA
VEA
C
is load resistor value, and
is compensation capacitor.
is the output filter capacitor,
CO
is the error amplifier transconductance, which is 200 x 10
=
=
=
is the error amplifier voltage gain, which is 500 V/V, and
is the equivalent series resistance of output capacitor.
----------------------------------- -
2
-------------------------------------------
2
------------------------------------------------- -
2
C
C
C
G
1
C
O
O
EA
1
G
R
ESR
L
VEA
CO
AOZ1014
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