IRF7350TRPBF International Rectifier, IRF7350TRPBF Datasheet - Page 8

• Manufacturer Part Number: IRF7350TRPBF
• Description: MOSFET N/P-CH 100V 2.1A 8-SOIC
• Manufacturer: International Rectifier
• Series: HEXFET®r

Specifications of IRF7350TRPBF

• Package / Case: 8-SOIC (3.9mm Width)
• Mounting Type: Surface Mount
• Power - Max: 2W
• Fet Type: N and P-Channel
• Gate Charge (qg) @ Vgs: 28nC @ 10V
• Vgs(th) (max) @ Id: 4V @ 250µA
• Current - Continuous Drain (id) @ 25° C: 2.1A, 1.5A
• Drain To Source Voltage (vdss): 100V
• Fet Feature: Standard
• Rds On (max) @ Id, Vgs: 210 mOhm @ 2.1A, 10V
• Transistor Polarity: N and P-Channel
• Drain-source Breakdown Voltage: 100 V
• Gate-source Breakdown Voltage: 20 V
• Continuous Drain Current: 2.1 A
• Power Dissipation: 2 W
• Mounting Style: SMD/SMT
• Gate Charge Qg: 19 nC
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

IRF7350
8
0.001
0.01
0.1
10
40
30
20
10
1
1.0E-06
0
Fig 20. Maximum Avalanche Energy
25
Duty Cycle = Single Pulse
Starting T J , Junction Temperature (°C)
0.05
0.10
0.01
1.0E-05
50
Vs. Temperature
TOP
BOTTOM 10% Duty Cycle
I D = 4.2A
75
1.0E-04
Fig 19. Typical Avalanche Current Vs.Pulsewidth
Single Pulse
100
1.0E-03
125
N-CHANNEL
1.0E-02
150
tav (sec)
Notes on Repetitive Avalanche Curves , Figures 15, 16:
(For further info, see AN-1005 at www.irf.com)
1. Avalanche failures assumption:
2. Safe operation in Avalanche is allowed as long asT
3. Equation below based on circuit and waveforms shown in
4. P
5. BV = Rated breakdown voltage (1.3 factor accounts for
6. I
7. T
Purely a thermal phenomenon and failure occurs at a
t
not exceeded.
Figures 12a, 12b.
T
D = Duty cycle in avalanche = t
Z
temperature far in excess of T
every part type.
avalanche pulse.
voltage increase during avalanche).
av
av =
thJC
D (ave)
jmax
= Allowable avalanche current.
=
1.0E-01
Average time in avalanche.
(D, t
Allowable rise in junction temperature, not to exceed
(assumed as 25°C in Figure 15, 16).
= Average power dissipation per single
av
P
) = Transient thermal resistance, see figure 11)
D (ave)
1.0E+00
Allowed avalanche Current vs
avalanche
assuming
avalanche losses
= 1/2 ( 1.3·BV·I
I
E
av
AS (AR)
= 2 T/ [1.3·BV·Z
= P
1.0E+01
D (ave)
pulsewidth,
jmax
Tj = 25°C due to
av
av
. This is validated for
·f
) = T/ Z
·t
th
av
]
www.irf.com
1.0E+02
thJC
tav
jmax
1.0E+03
is