LTC1060CN Linear Technology, LTC1060CN Datasheet - Page 10

• Manufacturer Part Number: LTC1060CN
• Description: IC FILTER BUILDING BLOCK 20-DIP
• Manufacturer: Linear Technology

Specifications of LTC1060CN

• Filter Type: Universal Switched Capacitor
• Frequency - Cutoff Or Center: 30kHz
• Number Of Filters: 2
• Max-order: 4th
• Voltage - Supply: ±2.37 V ~ 5 V
• Mounting Type: Through Hole
• Package / Case: 20-DIP (0.300", 7.62mm)
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant

W
DEFINITION
Table 3. Modes of Operation: 1st Order Functions
LTC1060
3. Highpass function: available only in mode 3 at the
4. Notch function: available at Pins 3 (18) for several
10
ouput Pins 3 (18). (Figure 3.)
modes of operation.
G(s) = (H
H
H
ODES OF OPERATIO
G(s) = H
H
ON2
ON1
f
OHP
n
MODE
0.707 H
U
= ω
6b
6a
7
= gain of the notch output for f→
= gain of the notch output for f→0
H
= gain of the HP output for f→
n
OBP
OBP
/2π; f
ON2
OHP
Q =
f
f
H
L
BANDPASS OUTPUT
)
Figure 1
n
U
f
= f
= f
H
s
is the frequency of the notch occurrence.
s
f
– f
0
0
0
2
2
f(LOG SCALE)
L
OF FILTER FUNCTIONS
–1
20
2Q
; f
+ s(ω
1
+ (sω
f
L
0
+
+
=
PIN 2 (19)
s
f
0
2
f
f
2Q
2Q
H
LP
LP
LP
L
1
1
+ ω
s
o
TLC1060 • DFF01
f
o
2
H
2
2
/Q) + ω
/Q) + ω
+ 1
+ 1
2
o
2
o
2
o
U
PIN 3 (18)
U
HP
LP
AP
f
0.707 H
CLK
f
2
CLK
2
H
H
OLP
OLP
H
OP
f
C
OP
f
P
= f
= f
U
= H
0
0
•
OLP
Figure 2
LOWPASS OUTPUT
1 –
•
1 –
f(LOG SCALE)
1
Q
2Q
2Q
1
1
2
5. Allpass function: available at Pins 3(18) for mode 4, 4a.
For allpass functions, the center frequency and the Q of
the numerator complex zero pair is the same as the
denominator. Under these conditions, the magnitude
response is a straight line. In mode 5, the center frequency
f
For high numerator Q’s, the magnitude response will have
a notch at f
2
f
z
1 –
P
1
, of the numerator complex zero pair, is different than f
+
4Q
f
1
C
G(s) = H
H
100(50)
100(50)
100(50)
1 –
2
OAP
f
f
f
CLK
CLK
TLC1060 • DFF02
CLK
2Q
1
2
2
= gain of the allpass output for 0 < f <
+ 1
•
•
z
f
•
C
.
R2
R3
R2
R3
OAP
R2
R3
[s
s
2
2
– s(ω
+ s(ω
0.707 H
H
f
f
C
P
OP
= f
= f
H
= H
H
OHP
OHP
0
0
o
o
OP
•
•
/Q) + ω
/Q) + ω
OHP
Figure 3
•
1 –
1 –
HIGHPASS OUTPUT
100(50)
Q
1
2Q
f(LOG SCALE)
1
2Q
f
f
1
CLK
C
2
2
2
2
1 –
o
o
1
]
+
f
– 1
P
4Q
1
•
2
1 –
R2
R3
f
2Q
TLC1060 • DFF03
Z
1
2
2
+ 1
– 1
f
CLK
2
1060fb
0
.