TS4994IQT STMicroelectronics, TS4994IQT Datasheet - Page 22

IC AMP AUDIO PWR 1W MONO 10DFN

TS4994IQT

Manufacturer Part Number
TS4994IQT
Description
IC AMP AUDIO PWR 1W MONO 10DFN
Manufacturer
STMicroelectronics
Type
Class ABr
Datasheet

Specifications of TS4994IQT

Output Type
1-Channel (Mono)
Max Output Power X Channels @ Load
1W x 1 @ 8 Ohm
Voltage - Supply
2.5 V ~ 5.5 V
Features
Depop, Differential Inputs, Short-Circuit and Thermal Protection, Standby
Mounting Type
Surface Mount
Package / Case
10-DFN
For Use With
497-6396 - BOARD EVAL FOR LV TS4984IQT497-6395 - BOARD EVAL FOR LP DIFF TS4994IQT
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

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Application information
4.4
22/35
the values of V
following formula:
with
The result of the calculation must be in the range:
If the result of the V
used.
Example: With V
higher than 2.5V - 0.9V = 1.6V, so input coupling capacitors are required. Alternatively, you
can change the V
Low and high frequency response
In the low frequency region, C
with a -3dB cut-off frequency. F
In the high-frequency region, you can limit the bandwidth by adding a capacitor (C
parallel with R
While these bandwidth limitations are in theory attractive, in practice, because of low
performance in terms of capacitor precision (and by consequence in terms of mismatching),
they deteriorate the values of PSRR and CMRR.
The influence of mismatching on PSRR and CMRR performance is discussed in more detail
in the following sections.
Example: A typical application with input coupling and feedback capacitor with F
and F
neglected. If we sweep the frequency from DC to 20kHz we observe the following with
respect to the PSRR value:
From DC to 200Hz, the C
C
CH
feed
= 8kHz. We assume that the mismatching between R
impedance is high enough to be neglected. Due to the tolerance of C
feed
CC
CC
, R
ic
. It forms a low-pass filter with a -3dB cut-off frequency. F
value.
ICM
=2.5V, R
in
and R
calculation is not in this range, an input coupling capacitor must be
V
ICM
feed
in
V
in
F
in
= R
=
ic
CL
CH
starts to have an effect. C
impedance decreases from infinite to a finite value and the
(
F
V
------------------------------------------------------------------------- -
=
A
CL
feed
is in Hz.
CC
=
V
0.6V V
Diff
------------------------------------------------------ -
). To have a good estimation of the V
2
=
×
2
×
= 20k and V
2
input+
R
π
×
×
in
×
π
(
R
ICM
R
+
×
in
feed
2
+
R
2
1
1
in
+
Diff
×
V
×
R
×
V
CC
C
feed
C
ic
input-
ic
in
feed
×
= 2V, we find V
)
0.9V
R
(
Hz
feed
(
in
)
Hz
forms, with R
(V)
)
in1,2
(V)
and C
ICM
= 1.63V. This is
in
ICM
feed1,2
, a high-pass filter
CH
value, use the
is in Hz.
can be
in1,2
CL
feed
= 50Hz
, we
TS4994
) in

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