C8051F575-IMR Silicon Labs, C8051F575-IMR Datasheet - Page 211

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C8051F575-IMR

Manufacturer Part Number
C8051F575-IMR
Description
8-bit Microcontrollers - MCU 50 MIPS 16 kB 2 kB SPI UART I2C
Manufacturer
Silicon Labs
Datasheet

Specifications of C8051F575-IMR

Rohs
yes
Core
8051
Processor Series
C8051
Data Bus Width
8 bit

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Part Number:
C8051F575-IMR
Manufacturer:
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Quantity:
290
The length of the 4 bit segments must be adjusted so that their sum is as close as possible to the desired
bit time. Since each segment must be an integer multiple of the time quantum (t
bit time is 24 tq (1000.008 ns), yielding a bit rate of 0.999992 Mbit/sec. The Sync_Seg is a constant 1 tq.
The Prop_Seg must be greater than or equal to the propagation delay of 400 ns and so the choice is 10 tq
(416.67 ns).
The remaining time quanta (13 tq) in the bit time are divided between Phase_Seg1 and Phase_Seg2 as
shown in. Based on this equation, Phase_Seg1 = 6 tq and Phase_Seg2 = 7 tq.
The Synchronization Jump Width (SJW) timing parameter is defined by. It is used for determining the value
written to the Bit Timing Register and for determining the required oscillator tolerance. Since we are using
a quartz crystal as the system clock source, an oscillator tolerance calculation is not needed.
The value written to the Bit Timing Register can be calculated using Equation 18.3. The BRP Extension
register is left at its reset value of 0x0000.
Bit Timing Register = (TSEG2 x 0x1000) + (TSEG1 x 0x0100) + (SJWp x 0x0040) + BRPE = 0x6FC0
1. If Phase_Seg1 + Phase_Seg2 is even, then Phase_Seg2 = Phase_Seg1. If the sum is odd, Phase_Seg2 =
2. Phase_Seg2 should be at least 2
Phase_Seg1 + 1.
1t
Phase_Seg1 + Phase_Seg2 = Bit_Time – (Synch_Seg + Prop_Seg)
Equation 21.3. Calculating the Bit Timing Register Value
q
Bit Timing Register = (TSEG2 x 0x1000) + (TSEG1 x 0x0100)
Equation 21.2. Synchronization Jump Width (SJW)
Sync_Seg
TSEG1 = Prop_Seg + Phase_Seg1 - 1 = 10 + 6 – 1 = 15
Equation 21.1. Assigning the Phase Segments
BRPE = BRP – 1 = BRP Extension Register = 0x0000
1t
Prop_Seg
Figure 21.3. Four segments of a CAN Bit
1 to 8 t
q
SJWp = SJW – 1 = minimum (4, 6) – 1 = 3
SJW = minimum (4, Phase_Seg1)
t
TSEG2 = Phase_Seg2 – 1 = 6
q
q
CAN Bit Time (4 to 25 t
.
Rev. 1.1
Phase_Seg1
1 to 8 t
q
C8051F55x/56x/57x
q
)
Phase_Seg2
Sample Point
1 to 8 t
q
), the closest achievable
q
211

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