ISL6730AFUZ Intersil, ISL6730AFUZ Datasheet - Page 16

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ISL6730AFUZ

Manufacturer Part Number
ISL6730AFUZ
Description
Power Factor Correction ICs PFC Controller
Manufacturer
Intersil
Datasheet

Specifications of ISL6730AFUZ

Rohs
yes
Switching Frequency
124 kHz
Maximum Operating Temperature
+ 125 C
Mounting Style
SMD/SMT
Package / Case
MSOP-10
Minimum Operating Temperature
- 40 C
INPUT VOLTAGE SETTING
First, set the BO resistor divider gain, K
Equation 1 and Equation 2.
Assuming the converter starts at V
resistor divider gain, K
K
In this design, two 3.3MΩ resistors in series are used for R
So, R
Using resistor from the standard value, R
K
K
NEGATIVE INPUT CAPACITOR GENERATION
The ISL6730A, ISL6730B, ISL6730C, ISL6730D generates an
equivalent negative capacitance at the input to cancel the input
filter capacitance. Thus, more input capacitors can be used
without reducing the power factor.
The input equivalent negative capacitance is a function of the
current sensing gain, BO resistor divider gain and the
compensation components.
C
C
This equivalent negative capacitor cancels the input filter
capacitor required for EMI filtering. Therefore, the displacement
power factor significantly improves.
R
BO
BO
BO
NEG
NEG
IN1
FIGURE 17. BODE PLOT OF THE ACTUAL CURRENT LOOP GAIN
is calculated:
IN1
=
=
=
=
=
------------------------
80V 2V
-------------------------------- -
R
------------------------------ -
1 0.00641
is calculated:
180
135
IN1
K
0.00647 0.8
-20
0.5V
0.00641
80
60
40
20
90
45
BO
R
0
0
10
IN1
+
R
0.8
IN2
=
0.00641
--------------- -
V
=
(
V
6.6MΩ
OUT
BO
100
0.00647
m
--------- -
390
1.5
should be:
ISL6730A, ISL6730B, ISL6730C, ISL6730D
------------------------- - C
R
FREQUENCY (Hz)
--------------------------- 18nF
0.068 1.9
)
CS
R
16
=
SEN
3.16k
A
42.6kΩ
1x10
iDC
LINE
(
3
(
ic
BO
= 80V
+
IN1
according to
C
10.5kHz
10.5kHz
1x10
ip
+
= 43kΩ, the actual
RMS
)
1.2nF
3
, then the BO
)
=
1x10
60
45
0.62μF
(EQ. 58)
(EQ. 59)
(EQ. 60)
(EQ. 57)
(EQ. 61)
IN2
3
.
For example, C
filter shown in Figure 13. When V
P
Assuming 95% efficiency under the above test condition, the
resistive component, which is in phase to voltage:
The reactive current through the input capacitors:
Thus, the displacement power factor is:
The reactive current generated by the equivalent negative
capacitor is:
With the equivalent negative capacitor, the total reactive current
reduces to:
The displacement power factor increases to:
VOLTAGE LOOP COMPENSATION
The average diode forward current can be approximated by:
Assuming the input current traces the input voltage perfectly. The
input power is in proportion to (V
Where Δ
R
I
I
PF
I
PF
I
I
I
I
a
c
cneg
D ave
D ave
c
D ave
O
IS
=
=
(
(
(
DIS
DIS
= 60W.
is the internal current scaling resistor. R
I
V
-------------------------------- -
V
cneg
=
LINE
LINE
)
)
=
=
)
=
=
=
V
COMP
P
-----------------------------------
------------------------------------------------------- -
LINE
-------------------------------------- -
R
0.598
--------------- -
V
=
o
( )
( )
P
OUT
CS
I
I
0.95
a
a
(
0.072A
in
2π f
R
2
2
I
is the V
F1
a
A
--- - Δ
V
SEN
+
+
0.5 R
(
2π f
=
( )
(
= 0.68µF, C
LINE
I
I
I
c
a
c
0.275A
COMP
2
LINE
IS
I
COMP
cneg
)
=
0.92
(
--------------- -
V
)
C
)
OUT
F1
2
1
- 1V. 1V is the offset voltage.
(
IN
C
=
+
NEG
= 0.94µF, using the low cost EMI
0.967
C
COMP
LINE
IN
----------------------------------------------- -
(
(
)
)
2 2
=
=
= 230VAC, f
- 1V).
0.045A
0.117A
) π ⁄
0.25
)
IS
2
= 16kΩ.
K
BO
LINE
February 26, 2013
Δ
= 50Hz,
COMP
FN8258.0
(EQ. 62)
(EQ. 63)
(EQ. 64)
(EQ. 65)
(EQ. 66)
(EQ. 67)
(EQ. 68)
(EQ. 69)
(EQ. 70)

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