AT91SAM9M10-G45-EK Atmel, AT91SAM9M10-G45-EK Datasheet - Page 581

KIT EVAL FOR AT91SAMG45/9M10

AT91SAM9M10-G45-EK

Manufacturer Part Number
AT91SAM9M10-G45-EK
Description
KIT EVAL FOR AT91SAMG45/9M10
Manufacturer
Atmel
Series
AT91SAM Smart ARMr
Type
MCUr
Datasheets

Specifications of AT91SAM9M10-G45-EK

Contents
Board, Cables, Power Supply
Processor To Be Evaluated
AT91SAM9M10
Processor Series
AT91SAM9
Data Bus Width
32 bit
Interface Type
RS-232, Ethernet, USB, JTAG
Operating Supply Voltage
5 V
Silicon Manufacturer
Atmel
Core Architecture
AVR
Kit Contents
Board
Features
Two High Speed USB Hosts, LCD TFT Display
Svhc
No SVHC (15-Dec-2010)
Mcu Supported Families
AT91SAM9M10,
Rohs Compliant
Yes
For Use With/related Products
AT91SAM9M10
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
AT91SAM9M10-G45-EK
Manufacturer:
INFINEON
Quantity:
10 000
Part Number:
AT91SAM9M10-G45-EK
Manufacturer:
Atmel
Quantity:
135
32.7.8.25
6355B–ATARM–21-Jun-10
Wake-up Request
Any node in a sleeping LIN cluster may request a wake-up.
In the LIN 2.0 specification, the wakeup request is issued by forcing the bus to the dominant
state from 250 μs to 5 ms. For this, it is necessary to send the character 0xF0 in order to impose
5 successive dominant bits. Whatever the baud rate is, this character respects the specified
timings.
In the LIN 1.3 specification, the wakeup request should be generated with the character 0x80 in
order to impose 8 successive dominant bits.
The user can choose by the WKUPTYP bit in the LIN Mode register (US_LINMR) either to send
a LIN 2.0 wakeup request (WKUPTYP=0) or to send a LIN 1.3 wakeup request (WKUPTYP=1).
A wake-up request is transmitted by writing the Control Register (US_CR) with the LINWKUP bit
at 1. Once the transfer is completed, the LINTC flag is asserted in the Status Register (US_SR).
It is cleared by writing the Control Register (US_CR) with the RSTSTA bit at 1.
• Baud rate min = 1 kbit/s -> Tbit = 1ms -> 5 Tbits = 5 ms
• Baud rate max = 20 kbit/s -> Tbi t= 50 μs -> 5 Tbits = 250 μs
AT91SAM9M10
581

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