IDT82V3255TFG8 IDT, Integrated Device Technology Inc, IDT82V3255TFG8 Datasheet - Page 111

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IDT82V3255TFG8

Manufacturer Part Number
IDT82V3255TFG8
Description
IC PLL WAN SMC STRATUM 3 64-TQFP
Manufacturer
IDT, Integrated Device Technology Inc
Type
PLL Clock Generatorr
Datasheet

Specifications of IDT82V3255TFG8

Input
CMOS, LVDS, PECL
Output
CMOS, LVDS, PECL
Frequency - Max
622.08MHz
Voltage - Supply
3 V ~ 3.6 V
Operating Temperature
-40°C ~ 85°C
Mounting Type
Surface Mount
Package / Case
64-TQFP, 64-VQFP
Frequency-max
622.08MHz
Function
Wan PLL
Operating Temperature (max)
85C
Operating Temperature (min)
-40C
Package Type
TQFP
Pin Count
64
Mounting
Surface Mount
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
82V3255TFG8

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Manufacturer:
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Table 35: Power Consumption and Maximum Junction Temperature
7
+85°C. To ensure the functionality and reliability of the device, the maxi-
mum junction temperature T
applications, the device will consume more power and a thermal solution
should be provided to ensure the junction temperature T
exceed the T
7.1
geographical center of the chip where the device's electrical circuits are.
It can be calculated as follows:
be used. The θ
in the loads.
ments.
7.2
Table 36: Thermal Data
Thermal Management
IDT82V3255
TQFP/EDG64
LQFP/PP64
The device operates over the industry temperature range -40°C ~
Junction temperature T
Where:
In order to calculate junction temperature, an appropriate θ
Power consumption is the core power excluding the power dissipated
Package
Assume:
TQFP/EDG64
TQFP/EDG64
LQFP/PP64
Package
Equation 1: T
θ
T
T
P = Device Power Consumption
T
θ
s)
P = 1.57W
A
A
JA
j
JA
= Junction Temperature
= 85°C
= Ambient Temperature
= 21.7°C/W (TQFP/EDG64 Soldered & when airfow rate is 0 m/
= Junction-to-Ambient Thermal Resistance of the Package
THERMAL MANAGEMENT
JUNCTION TEMPERATURE
EXAMPLE OF JUNCTION TEMPERATURE
CALCULATION
jmax
Table 35
JA
Consumption (W)
.
is shown in
Pin Count Thermal Pad
j
Power
= T
1.57
1.57
provides power consumption in special environ-
64
64
64
A
+ P X
j
is the temperature of package typically at the
jmax
Table
θ
Yes/Soldered
Yes/Exposed
JA
should not exceed 125°C. In some
Operating
36:
Voltage
No
(V)
3.6
3.6
T
A
θ
85
85
(°C)
JC
12.3
12.6
12.6
(°C/W)
Temperature (°C)
Maximum
Junction
j
125
125
does not
JA
θ
JB
must
35.1
35.3
1.3
(°C/W)
111
temperature of 125°C so no extra heat enhancement is required.
might exceed the maximum junction temperature of 125°C and an exter-
nal thermal solution such as a heatsink is required.
7.3
attached. θ
resistance, as the heat flowing from the die junction to ambient goes
through the package and the heatsink. θ
be selected to ensure the junction temperature does not exceed the
maximum junction temperature. According to Equation 1 and 2,
below or equal to 12.9°C/W is used in such operation environment, the
junction temperature will not exceed the maximum junction temperature.
The junction temperature T
The junction temperature of 119.1°C is below the maximum junction
In some operation environments, the calculated junction temperature
A heatsink is expanding the surface area of the device to which it is
Where:
θ
Assume:
θ
That is, if a heatsink and heatsink attachment whose θ
θ
CH
CH
CH
43.1
37.0
21.7
+ θ
+ θ
0
T
Equation 2:
θ
θ
θ
Equation 3:
T
T
P = 1.57W
θ
θ
+ θ
A
j
JC
CH
HA
j
JC
CH
= T
= 125°C (T
HA
= 85°C
HA
HA
JA
+
= Junction-to-Case Thermal Resistance
= 12.6°C/W (TQFP/EDG64)
= Case-to-Heatsink Thermal Resistance
= Heatsink-to-Ambient Thermal Resistance
HEATSINK EVALUATION
A
θ
can be calculated as follows:
is now a combination of device case and heat-sink thermal
determines which heatsink and heatsink attachment can
can be calculated as follows:
+ P X
HA
32.1
17.3
= (125°C - 85°C ) / 1.57W - 12.6°C/W = 12.9°C/W
40
1
θ
θ
jmax
θ
JA
CH
JA
+
=
)
= 85°C + 1.57W X 21.7°C/W = 119.1°C
θ
θ
θ
JA
HA
JC
(°C/W) Air Flow in m/s
38.1
30.4
16.2
+
= (T
j
2
θ
can be calculated as follows:
CH
j
- T
+
A
θ
) / P -
HA
JA
37.3
29.4
15.6
3
θ
can be calculated as follows:
JC
December 3, 2008
36.5
28.7
15.2
4
CH
WAN PLL
+
36.1
28.1
14.9
θ
5
HA
is

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