LT1952EGN-1#PBF Linear Technology, LT1952EGN-1#PBF Datasheet - Page 19

• Manufacturer Part Number: LT1952EGN-1#PBF
• Description: IC CTLR PWM SGL SWITCH 16-SSOP
• Manufacturer: Linear Technology

Specifications of LT1952EGN-1#PBF

• Pwm Type: Current Mode
• Number Of Outputs: 1
• Frequency - Max: 560kHz
• Duty Cycle: 90%
• Voltage - Supply: 6.82 V ~ 25 V
• Buck: No
• Boost: No
• Flyback: Yes
• Inverting: No
• Doubler: No
• Divider: No
• Cuk: No
• Isolated: Yes
• Operating Temperature: -40°C ~ 125°C
• Package / Case: 16-SSOP
• Frequency-max: 560kHz
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

APPLICATIONS INFORMATION
This gives k = 1 and t
Re-arranging the above equation to solve for SS_MAXDC
= V
Step 3: Calculate t(V
Recall the time for SS_MAXDC to charge to a given voltage
V
(Figure 11 gives the model for SS_MAXDC charging)
The rise time for the converter output
Example (3) Time For Maximum Duty Cycle Clamp to
Reach Within X% of Target Value
A maximum duty cycle clamp of 72% was calculated
previously in the section ‘Programming Maximum
Duty Cycle Clamp’. The programmed value used for
SS_MAXDC(DC) was 1.84V.
The time for SS_MAXDC to charge from its minimum value
V
From previous calculations, t(0.45) = 7.3e – 4 s.
Using previous values for R
SS
SS(MIN)
For SD_V
= [0.6 + (t
= [0.6 + (40ns • 200kHz)(1.32V)]/(1 • 0.522)
= (0.608)(1.32)/0.522 = 1.537V
t = R
For R
For C
= t(V
= 2.63e
t(V
ln(1 – 1.66/1.84) = 2.63e
= 5e
= t(V
= 3.5e
t(SS_MAXDC charge time within X% of target)
= t[(1 – (X/100) • SS_MAXDC(DC)] – t(V
For X = 2 and V
t(0.45) = t(1.803) – t(0.45)
SS(REG)
is given by:
SS(REG)
–3
CHARGE
SS(0.8V)
SS(REG)
T
SS
–3
to within X% of SS_MAXDC(DC) is given by:
= 35.7k, R
s
–3
= 0.1μF, this gives t(V
s
SEC
DELAY
) = t(V
• (–1) • ln(0.565) = 1.5e
) – t(V
• C
) = 2.63e
= 1.32V, fOSC = 200kHz and R
SS
SS(MIN)
• f
SS(1.537V)
B
SS(REG)
• (–1) • ln(1 – V
OSC
SS(ACTIVE)
DELAY
= 100k, R
4
)(SD_V
• 1e
= 0.45V, t(0.98 • 1.84) –
= 40ns.
) – t(V
T
–3
) = 26.3k • 0.1μF • –1 •
, R
–7
• (–1) • ln(0.146)
) = (5 – 1.5)e
CHARGE
B
SEC
• (–1) • ln(1 – 0.8/1.84)
SS(ACTIVE)
, and C
SS(ACTIVE)
)]/(k • 0.522)
SS
–3
/SS_MAXDC(DC))
= 26.3k
SS
s
,
)
)
SS(MIN)
–3
DELAY
s
= 40k
)
Hence the time for SS_MAXDC to charge from its minimum
reset threshold of 0.45V to within 2% of its target value
is given by:
Forward Converter Applications
The following section covers applications where the
LT1952/LT1952-1 are used in conjunction with other LTC
parts to provide highly effi cient power converters using
the single switch forward converter topology.
95% Effi cient, 5V, Synchronous Forward Converter
The circuit in Figure 14 is based on the LT1952-1 to provide
the simplest forward power converter circuit—using only
one primary MOSFET. The SOUT pin of the LT1952-1
provides a synchronous control signal for the LTC1698
located on the secondary. The LTC1698 drives secondary
side synchronous rectifi er MOSFETs to achieve high
effi ciency. The LTC1698 also serves as an error amplifi er
and optocoupler driver.
Effi ciency and transient response are shown in Figures 12
and 13. Peak effi ciencies of 95% and ultra-fast transient
response are superior to presently available power
modules. Integrated soft-start, overcurrent detection and
short-circuit hiccup mode provide low stress, reliable
protection. In addition, the circuit in Figure 14 is an all-
ceramic capacitor solution providing low output ripple
voltage and improved reliability. The LT1952-based
converter can be used to replace power module converters
at a much lower cost. The LT1952 solution benefi ts from
thermal conduction of the system board resulting in higher
effi ciencies and lower rise in component temperatures. The
7mm height allows dense packaging and the circuit can
easily be adjusted to provide an output voltage from 1.23V
to 26V. Higher currents are achievable by simple scaling
of power components. The LT1952-1-based solution in
Figure 14 is a powerful topology for replacement of a wide
range of power modules.
t(1.803) = 2.63e
= 2.63e
t(1.803) – t(0.45) =
1.03e
–2
–3
– 7.3e
• (–1) • ln(0.02) = 1.03e
–4
–4
= 9.57e
• 1e
LT1952/LT1952-1
–7
–3
• (–1) • ln(1 – 1.803/1.84)
–2
s
19
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