FDS8934A Fairchild Semiconductor, FDS8934A Datasheet - Page 4

• Manufacturer Part Number: FDS8934A
• Description: MOSFET P-CH DUAL 20V 4A 8SOIC
• Manufacturer: Fairchild Semiconductor

Specifications of FDS8934A

• Fet Type: 2 P-Channel (Dual)
• Fet Feature: Logic Level Gate
• Rds On (max) @ Id, Vgs: 55 mOhm @ 4A, 4.5V
• Drain To Source Voltage (vdss): 20V
• Current - Continuous Drain (id) @ 25° C: 4A
• Vgs(th) (max) @ Id: 1V @ 250µA
• Gate Charge (qg) @ Vgs: 28nC @ 5V
• Input Capacitance (ciss) @ Vds: 1130pF @ 10V
• Power - Max: 900mW
• Mounting Type: Surface Mount
• Package / Case: 8-SOIC (3.9mm Width)
• Configuration: Dual Dual Drain
• Transistor Polarity: P-Channel
• Resistance Drain-source Rds (on): 0.055 Ohms
• Forward Transconductance Gfs (max / Min): 13 S
• Drain-source Breakdown Voltage: - 20 V
• Gate-source Breakdown Voltage: - 8 V
• Continuous Drain Current: 4 A
• Power Dissipation: 2 W
• Maximum Operating Temperature: + 150 C
• Mounting Style: SMD/SMT
• Minimum Operating Temperature: - 55 C
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

Typical Electrical Characteristics
0.03
0.01
5
4
3
2
1
0
0.3
0.1
0
50
20
10
Figure 7. Gate Charge Characteristics.
5
1
Figure 9. Maximum Safe Operating Area.
0.1
I
D
=-4.0A
SINGLE PULSE
R
0.005
0.002
0.001
0.05
0.02
0.01
0.2
V
JA
0.5
0.2
0.1
T = 25°C
0.0001
GS
A
1
A
4
= 135°C/W
= -4.5V
- V
0.5
Q
DS
g
D = 0.5
, DRAIN-SOURCE VOLTAGE (V)
, GATE CHARGE (nC)
8
1
0.2
Figure 11. Transient Thermal Response Curve.
0.1
0.05
0.001
0.02
2
0.01
12
Single Pulse
V
Thermal characterization performed using the conditions described in Note 1c.
DS
Transient thermal response will change depending on the circuit board design.
5
= -5V
-15V
16
10
0.01
-10V
20 30
20
(continued)
50
0.1
t , TIME (sec)
1
3000
2000
1000
500
200
100
50
40
30
20
10
0.001
50
0
0.1
Figure 10. Single Pulse Maximum Power
Figure 8. Capacitance Characteristics.
f = 1 MHz
V
GS
1
= 0 V
0.2
0.01
-V
DS
, DRAIN TO SOURCE VOLTAGE (V)
0.5
SINGLE PULSE TIME (SEC)
Dissipation.
0.1
P(pk)
T - T
R
10
1
Duty Cycle, D = t /t
J
R
JA
t
1
A
JA
(t) = r(t) * R
t
= P * R
1
2
2
= 135°C/W
1
SINGLE PULSE
JA
R
10
(t)
2
JA
5
T = 25°C
JA
100
A
=135°C/W
10
C iss
C oss
C rss
FDS8934A Rev.B
100
300
20
300