FJV992FMTF Fairchild Semiconductor, FJV992FMTF Datasheet - Page 2

• Manufacturer Part Number: FJV992FMTF
• Description: TRANSISTOR PNP 120V 50MA SOT-23
• Manufacturer: Fairchild Semiconductor

Specifications of FJV992FMTF

• Transistor Type: PNP
• Current - Collector (ic) (max): 50mA
• Voltage - Collector Emitter Breakdown (max): 120V
• Vce Saturation (max) @ Ib, Ic: 300mV @ 1mA, 10mA
• Dc Current Gain (hfe) (min) @ Ic, Vce: 300 @ 1mA, 6V
• Power - Max: 300mW
• Frequency - Transition: 50MHz
• Mounting Type: Surface Mount
• Package / Case: SOT-23-3, TO-236-3, Micro3™, SSD3, SST3
• Configuration: Single
• Transistor Polarity: PNP
• Mounting Style: SMD/SMT
• Collector- Emitter Voltage Vceo Max: 120 V
• Emitter- Base Voltage Vebo: - 5 V
• Continuous Collector Current: - 0.05 A
• Maximum Dc Collector Current: 0.05 A
• Power Dissipation: 0.3 W
• Maximum Operating Frequency: 50 MHz
• Maximum Operating Temperature: + 150 C
• Dc Collector/base Gain Hfe Min: 200
• Minimum Operating Temperature: - 55 C
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Current - Collector Cutoff (max): -
• Lead Free Status / Rohs Status: Lead free / RoHS Compliant

©2004 Fairchild Semiconductor Corporation
Typical Characteristics
Figure 5. Base-Emitter Saturation Voltage
1000
0.1
100
-1.0
-0.8
-0.6
-0.4
-0.2
1
1E-3
10
0.0
-1E-3
0
Figure 1. Static Characteristic
Ta=125
Ta=-25
Ta=25
Ta=-25
Ta=125
Ta=25
Figure 3. DC current Gain
V
0
0
0
C
0
0
C
0
-20
CE
C
C
C
I
C
C
I
[mA], COLLECTOR CURRENT
[V], COLLECTOR-EMITTER VOLTAGE
C
[mA], COLLECTOR CURRENT
-0.01
I
B
0.01
-40
= -1.2 A
I
B
= -1.2 A
-60
I
B
= 0
I
B
= -1.0 A
-0.1
I
B
I
-80
C
I
= -0.8 A
B
=10I
V
I
0.1
I
= -0.6 A
B
B
CE
= -0.4 A
= -0.2 A
=-6V
B
-100
Figure 4. Collector-Emitter Saturation Voltage
-0.01
-0.1
-0.12
-0.10
-0.08
-0.06
-0.04
-0.02
-0.00
-10
-1
-1E-3
-8
-6
-4
-2
0
-0.2
0
Ta=-25
Ta=25
Figure 6. Base-Emitter Voltage
Figure 2. Static Characteristic
I
B
= -24 A
0
0
C
C
V
CE
-1
I
V
Ta=125
C
[V], COLLECTOR-EMITTER VOLTAGE
BE
[mA], COLLECTOR CURRENT
-0.4
[V], BASE-EMITTER VOLTAGE
0
C
-0.01
Ta=125
-2
-0.6
0
C
Ta=25
-3
I
I
I
I
I
I
B
B
B
B
B
B
= -20 A
= -16 A
= 0
= -12 A
= -8 A
= -4 A
0
C
-0.8
I
C
=10I
-4
V
Ta=-25
CE
-0.1
=-6V
B
0
C
Rev. C, August 2004
-1.0
-5