PIC18F25J50 MICROCHIP [Microchip Technology], PIC18F25J50 Datasheet - Page 471

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PIC18F25J50

Manufacturer Part Number
PIC18F25J50
Description
28/44-Pin, Low-Power, High-Performance USB Microcontrollers with nanoWatt XLP Technology
Manufacturer
MICROCHIP [Microchip Technology]
Datasheet

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SUBLW
Syntax:
Operands:
Operation:
Status Affected:
Encoding:
Description:
Words:
Cycles:
Example 1:
Example 2:
Example 3:
 2011 Microchip Technology Inc.
Q Cycle Activity:
Before Instruction
After Instruction
Before Instruction
After Instruction
Before Instruction
After Instruction
Decode
W
C
W
C
Z
N
W
C
W
C
Z
N
W
C
W
C
Z
N
Q1
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
literal ‘k’
Subtract W from Literal
SUBLW k
0 k 255
k – (W) W
N, OV, C, DC, Z
W is subtracted from the eight-bit
literal ‘k’. The result is placed in W.
1
1
SUBLW
SUBLW
SUBLW
Read
Q2
0000
01h
?
01h
1
0
0
02h
?
00h
1
1
0
03h
?
FFh
0
0
1
; result is positive
; result is zero
; result is negative
; (2’s complement)
0x02
0x02
0x02
1000
Process
Data
Q3
kkkk
Write to
Q4
W
kkkk
PIC18F46J50 FAMILY
SUBWF
Syntax:
Operands:
Operation:
Status Affected:
Encoding:
Description:
Words:
Cycles:
Example 1:
Example 2:
Example 3:
Q Cycle Activity:
Before Instruction
After Instruction
Before Instruction
After Instruction
Before Instruction
After Instruction
Decode
REG
W
C
REG
W
C
Z
N
REG
W
C
REG
W
C
Z
N
REG
W
C
REG
W
C
Z
N
Q1
Subtract W from f
SUBWF
0 f 255
d  [0,1]
a  [0,1]
(f) – (W) dest
N, OV, C, DC, Z
Subtract W from register, ‘f’ (2’s
complement method). If ‘d’ is ‘0’, the
result is stored in W. If ‘d’ is ‘1’, the result
is stored back in register, ‘f’ (default).
If ‘a’ is ‘0’, the Access Bank is selected.
If ‘a’ is ‘1’, the BSR is used to select the
GPR bank (default).
If ‘a’ is ‘0’ and the extended instruction
set is enabled, this instruction operates
in Indexed Literal Offset Addressing
mode whenever f 95 (5Fh). See
Section 28.2.3 “Byte-Oriented and
Bit-Oriented Instructions in Indexed
Literal Offset Mode”
1
1
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
=
register ‘f’
0101
SUBWF
SUBWF
SUBWF
Read
Q2
3
2
?
1
2
1
0
0
2
2
?
2
0
1
1
0
1
2
?
FFh ;(2’s complement)
2
0
0
1
f {,d {,a}}
; result is positive
; result is zero
; result is negative
11da
REG, 1, 0
REG, 0, 0
REG, 1, 0
Process
Data
Q3
DS39931D-page 471
for details.
ffff
destination
Write to
Q4
ffff

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