IDT82P2284 Integrated Device Technology, Inc., IDT82P2284 Datasheet - Page 355

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IDT82P2284

Manufacturer Part Number
IDT82P2284
Description
4 Channel T1/J1/E1 Transceiver
Manufacturer
Integrated Device Technology, Inc.
Datasheet

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IDT82P2284
TPLC:
timeslot.
responds to one timeslot.
TS15 and TS17 to TS31 respectively. Each address corresponds to one timeslot.
E1 Timeslot Control Register (00H ~ 1FH)
SUBST[2:0]:
SINV, OINV, EINV:
Programming Information
SUBST[2:0]
Bit Name
Default
Bit No.
Type
The indirect registers of TPLC addressed from 00H to 1FH are the Timeslot Control Registers for TS0 to TS31. Each address corresponds to one
The indirect registers of TPLC addressed from 20H to 3FH are the Data Trunk Conditioning Code Registers for TS0 to TS31. Each address cor-
The indirect registers of TPLC addressed from 41H to 4FH and from 51H to 5FH are the Signaling Trunk Conditioning Code Registers for TS1 to
When the GSUBST[2:0] bits(b2~0, E1-0CBH,...) are ‘000’, these bits select the replacement on a per-channel basis.
These three bits select how to invert the bits in the corresponding channel.
others
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
SINV
0
0
0
0
1
1
1
1
No operation.
The data of the corresponding timeslot is replaced by the data trunk code set in the DTRK[7:0] bits (b7~0, T1/J1-ID-21~38H).
The data of the corresponding timeslot is replaced by the A-Law digital milliwatt pattern.
The data of the corresponding timeslot is replaced by the µ-Law digital milliwatt pattern.
The data of the corresponding timeslot is replaced by the payload loopback code extracted from the Elastic Store Buffer in the receive path.
Reserved.
SUBST2
R/W
7
0
OINV
0
0
1
1
0
0
1
1
EINV
0
1
0
1
0
1
0
1
SUBST1
R/W
6
0
No inversion.
Invert the even bits (bit 2, 4, 6, 8) of the corresponding channel (bit 1 is the MSB).
Invert the odd bits (bit 3, 5, 7) except the MSB of the corresponding channel (bit 1 is the MSB).
Invert the bits from bit 2 to bit 8 of the corresponding channel (bit 1 is the MSB).
Invert the MSB (bit 1) of the corresponding channel.
Invert the MSB (bit 1) and the even bits (bit 2, 4, 6, 8) of the corresponding channel.
Invert all the odd bits (bit 1, 3, 5, 7) of the corresponding channel (bit 1 is the MSB).
Invert all the bits (bit 1 ~ bit 8) of the corresponding channel (bit 1 is the MSB).
SUBST0
R/W
5
0
SINV
R/W
Replacement Selection
4
0
344
QUAD T1/E1/J1 LONG HAUL / SHORT HAUL TRANSCEIVER
Bit Inversion
OINV
R/W
3
0
EINV
R/W
2
0
G56K
R/W
1
0
March 22, 2004
GAP
R/W
0
0

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