ST92E163-EPB/US STMicroelectronics, ST92E163-EPB/US Datasheet - Page 51

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ST92E163-EPB/US

Manufacturer Part Number
ST92E163-EPB/US
Description
KIT DEMO MASS STORAGE
Manufacturer
STMicroelectronics
Type
Microcontroller Programmerr
Datasheet

Specifications of ST92E163-EPB/US

Contents
Programmer, Cable, Power Supply, Software, Manual and more
For Use With/related Products
ST9 MCUs
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

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0
ARBITRATION MODES (Cont’d)
Example 2
In the second example, (more complex,
23), each interrupt service routine sets Interrupt
Enable with the ei instruction at the beginning of
the routine. Placed here, it minimizes response
time for requests with a higher priority than the one
being serviced.
The level 2 interrupt routine (with the highest prior-
ity) will be acknowledged first, then, when the ei
instruction is executed, it will be interrupted by the
level 3 interrupt routine, which itself will be inter-
rupted by the level 4 interrupt routine. When the
level 4 interrupt routine is completed, the level 3 in-
terrupt routine resumes and finally the level 2 inter-
rupt routine. This results in the three interrupt serv-
Figure 23. Complex Example of a Sequence of Interrupt Requests with:
- Concurrent mode selected
- IEN set to 1 during interrupt service routine execution
0
1
2
3
4
5
6
7
CPL is set to 7
Priority Level of
Interrupt Request
MAIN
INT 5
ei
CPL = 7
INT 5
INT 2
INT 3
INT 4
ei
CPL = 7
INT 2
ei
CPL = 7
INT 3
Figure
ei
ei
CPL = 7
INT 4
ice routines being executed in the opposite order
of their priority.
It is therefore recommended to avoid inserting
the ei instruction in the interrupt service rou-
tine in Concurrent mode. Use the ei instruc-
tion only in nested mode.
IMPORTANT: If, in Concurrent Mode, interrupts
are nested (by executing ei in an interrupt service
routine), make sure that either ENCSR is set or
CSR=ISR, otherwise the iret of the innermost in-
terrupt will make the CPU use CSR instead of ISR
before the outermost interrupt service routine is
terminated, thus making the outermost routine fail.
CPL = 7
INT 3
INTERRUPT 2 HAS PRIORITY LEVEL 2
INTERRUPT 3 HAS PRIORITY LEVEL 3
INTERRUPT 4 HAS PRIORITY LEVEL 4
INTERRUPT 5 HAS PRIORITY LEVEL 5
CPL = 7
ST92163R4 - INTERRUPTS
INT 2
CPL = 7
INT 5
CPL = 7
MAIN
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