27403 Parallax Inc, 27403 Datasheet - Page 37

GUIDE APP ROBOTCS W/SUMOBOT V1.0

27403

Manufacturer Part Number
27403
Description
GUIDE APP ROBOTCS W/SUMOBOT V1.0
Manufacturer
Parallax Inc
Datasheet

Specifications of 27403

Accessory Type
Manual
Product
Microcontroller Accessories
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
For Use With/related Products
SumoBot®
Lead Free Status / RoHS Status
Lead free / RoHS Compliant, Contains lead / RoHS non-compliant
Next, convert to the corresponding units of force (newtons):
Finally, plug these forces into the coefficient of kinetic friction equation and calculate the
result:
Coefficients of friction make predicting how much force it will take to get something to
slide really easy. The same applies for sustained sliding and the coefficient of kinetic
friction. In either case, all you have to do is multiply the normal force by the coefficient
of friction.
When the surface is tilting, the normal force takes some extra calculating, but when it's
horizontal to the ground, like in Figure 1-8, the normal force is just the object's weight on
the surface. The force to start it sliding is the coefficient of friction multiplied by the
object's weight, and the force to keep it sliding is the coefficient of kinetic friction
multiplied by the object's weight.
N
µ
W
f
f
f
S
S
S
S
=
=
=
=
=
=
=
=
=
2
=
20
. 6
0
mg
µ
µ
1 .
. 0
7 .
f
20
N
86
S
S
K
. 6
.
kg
58
333
kg
Why couldn't I have just used the ratio of the masses? For this particular problem on the
earth's surface, you can use this shortcut. The ratio of the masses does give you the correct
answer, 700/2100 = 0.333... However, you should always keep in mind that the µ
are ratios of forces. While you won't encounter it in this book, the problems get more
complex when they incorporate things like thrust and a body's tendency to rotate.
general, when the problems get more complex, you will have to be strict about the difference
between mass and force.
×
×
86
.
N
58
N
W
N
×
×
N
...
9
N
9
8 .
and
8 .
and
m
m
s /
s /
f
2
K
f
2
K
=
=
µ
µ
K
K
×
×
N
W
Chapter 1: Mechanical Adjustments · Page 33
s
and µ
In
k

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