EP1S40B956C5 Altera, EP1S40B956C5 Datasheet - Page 599

IC STRATIX FPGA 40K LE 956-BGA

EP1S40B956C5

Manufacturer Part Number
EP1S40B956C5
Description
IC STRATIX FPGA 40K LE 956-BGA
Manufacturer
Altera
Series
Stratix®r
Datasheet

Specifications of EP1S40B956C5

Number Of Logic Elements/cells
41250
Number Of Labs/clbs
4125
Total Ram Bits
3423744
Number Of I /o
683
Voltage - Supply
1.425 V ~ 1.575 V
Mounting Type
Surface Mount
Operating Temperature
0°C ~ 85°C
Package / Case
956-BGA
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Number Of Gates
-

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Altera Corporation
September 2004
Implementing High Performance DSP Functions in Stratix & Stratix GX Devices
required is 16
number of computations per cycle required is 4
there are four polyphase filters, each with four taps.
Figure 7–12. Polyphase Representation of I=4 Interpolation Filter
Polyphase Interpolation Filter Implementation
Figure 7–13
polyphase interpolation filter in
share the same hardware, which is a 4-tap filter. One Stratix or Stratix GX
DSP block can implement one 4-tap filter with 18-bit wide data and
coefficients. A multiplexer can be used to load new coefficient values on
every cycle of the 4 clock. Stratix and Stratix GX phase lock loops (PLLs)
can generate the 4 clock. In the first cycle of the 4 clock, the user needs
to load coefficients for polyphase filter h
Interpolation Using a Single Low-Pass Filter
Interpolation Using a Polyphase Filter
Input
Input
x(n)
x(n)
shows the Stratix or Stratix GX implementation of the
I = 16
I = 4
h(2), h(6), h(10), h(14)
h(3), h(7), h(11), h(15)
h(0), h(4), h(8), h(12)
h(1), h(5), h(9), h(13)
with coefficients
with coefficients
with coefficients
with coefficients
Polyphase filter
Polyphase filter
Polyphase filter
Polyphase filter
4 = 64. In the polyphase implementation, the
Figure
4x Clock
h(0), h(1), ... h(15)
coefficients
y4(n)
y1(n)
y2(n)
y3(n)
Stratix Device Handbook, Volume 2
7–12. The four polyphase filters
0
LPF with
(n); in the second cycle of the 4
initialized at 0
Modulo 4 up
counter
4 = 16. This is because
0
2
3
1
Output
y(n)
Output
y(n)
7–21

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